Oh No R Programmerhumor A good leaving group has to be able to part with its electrons easily enough, so typically, it must be a strong acid or weak base relative to other substituents on the same molecule. it helps to know the pka of what would be leaving. let's say you had a mechanism where you are trying to do an e2 reaction to make an oh (hydroxyl) group leave. maybe you have this compound on hand, sec butanol. Mg (oh) 2 now we know that hydroxides are salts of ho^ , and some metal ion. now if the parent metal has an electronic configuration of 2:8:2, then there are 12 electrons, and the atomic number of the metal is equal to 12. we look on the periodic table, and we find that z=12, for "magnesium metal". as a group 2 metal, magnesium forms a mg^ (2 ) ion, and hence its hydroxide is mg (oh) 2.
Oh No R Programmerhumor Lithium is a group 1 metal and commonly forms a m ion. hydroxide anion, −oh, has a unit negative charge. when they make music together, there is thus 1:1 stoichiometry between ions: li(s) h 2o(l) → lioh (aq) 1 2 h 2(g) ↑ ⏐ ⏐⏐. The nitrate and the natrium ions. na 2co 3(aq) 2agno 3(aq) rarr ag 2co 3(s)darr 2nano 3(aq) the net ionic equation is: 2ag^( ) co 3^(2 ) rarr ag 2co 3(s)darr. M g(oh)2(s) ⇌ m g2 (aq) 2oh − (aq) in order to determine the maximum concentration of m g2 ions permissible in the n aoh solution before a precipitate will be formed, you'd need the value of the solubility product constant, ksp. The acid in excess is then titrated with n aoh (aq) of known concentration .we can thus get back to the concentration or molar quantity of m (oh)2 as it stands the question (and answer) are hypothetical.
Oh No R Programmerhumor M g(oh)2(s) ⇌ m g2 (aq) 2oh − (aq) in order to determine the maximum concentration of m g2 ions permissible in the n aoh solution before a precipitate will be formed, you'd need the value of the solubility product constant, ksp. The acid in excess is then titrated with n aoh (aq) of known concentration .we can thus get back to the concentration or molar quantity of m (oh)2 as it stands the question (and answer) are hypothetical. The degree of dissociation sf (alpha=0.0158) sf (k b=2.51xx10^ ( 6)color (white) (x)"mol l") triethyamine is a weak base and ionises: sf ( (ch 3) 3n h 2orightleftharpoons (ch 3) 3stackrel ( ) (n)h oh^ ) for which: sf (k b= ( [ (ch 3) 3stackrel ( ) (n)h] [oh^ ( )]) ( [ (ch 3) 3n])) rearranging and taking ve logs of both sides we get the. These are ostensibly acid base reactions . for ammonium we could write . nh 4^ ho^( ) rarr nh 3(aq) h 2o(l) for methanol, the acid base reaction would proceed. In order to compute the mass percent of hydrogen in c3h 5oh we're going to need two things: 1: the formula mass of the entire compound 2: the atomic mass of hydrogen the formula mass of c3h 5oh is 58.08 g mol because: 3(12.01 g mol) 6(1.008 g mol) (16.00 g mol) = 58.08 g mol the atomic mass of the hydrogen atom is 1.008 g mol now, we have to use the following equation: the numerator. The phenolphthalein alkalinity is "15.1 meq caco" 3" l"; the total alkalinity is "23.6 meq caco" 3" l". alkalinity in water is caused by the presence of "hco" 3^ , "co" 3^(2 ) and "oh"^ ions. phenolphthalein alkalinity is determined by titration to a phenolphthalein end point (ph 8.3). it indicates the total hydroxide and half the carbonate present. titration to a methyl orange end point (ph.
Oh No R Programmerhumor The degree of dissociation sf (alpha=0.0158) sf (k b=2.51xx10^ ( 6)color (white) (x)"mol l") triethyamine is a weak base and ionises: sf ( (ch 3) 3n h 2orightleftharpoons (ch 3) 3stackrel ( ) (n)h oh^ ) for which: sf (k b= ( [ (ch 3) 3stackrel ( ) (n)h] [oh^ ( )]) ( [ (ch 3) 3n])) rearranging and taking ve logs of both sides we get the. These are ostensibly acid base reactions . for ammonium we could write . nh 4^ ho^( ) rarr nh 3(aq) h 2o(l) for methanol, the acid base reaction would proceed. In order to compute the mass percent of hydrogen in c3h 5oh we're going to need two things: 1: the formula mass of the entire compound 2: the atomic mass of hydrogen the formula mass of c3h 5oh is 58.08 g mol because: 3(12.01 g mol) 6(1.008 g mol) (16.00 g mol) = 58.08 g mol the atomic mass of the hydrogen atom is 1.008 g mol now, we have to use the following equation: the numerator. The phenolphthalein alkalinity is "15.1 meq caco" 3" l"; the total alkalinity is "23.6 meq caco" 3" l". alkalinity in water is caused by the presence of "hco" 3^ , "co" 3^(2 ) and "oh"^ ions. phenolphthalein alkalinity is determined by titration to a phenolphthalein end point (ph 8.3). it indicates the total hydroxide and half the carbonate present. titration to a methyl orange end point (ph.
Oh No R Programmerhumor In order to compute the mass percent of hydrogen in c3h 5oh we're going to need two things: 1: the formula mass of the entire compound 2: the atomic mass of hydrogen the formula mass of c3h 5oh is 58.08 g mol because: 3(12.01 g mol) 6(1.008 g mol) (16.00 g mol) = 58.08 g mol the atomic mass of the hydrogen atom is 1.008 g mol now, we have to use the following equation: the numerator. The phenolphthalein alkalinity is "15.1 meq caco" 3" l"; the total alkalinity is "23.6 meq caco" 3" l". alkalinity in water is caused by the presence of "hco" 3^ , "co" 3^(2 ) and "oh"^ ions. phenolphthalein alkalinity is determined by titration to a phenolphthalein end point (ph 8.3). it indicates the total hydroxide and half the carbonate present. titration to a methyl orange end point (ph.
Oh No R Programmerhumor
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