71 D48993 E4 B3 478 F A1 A2 0 F4 E9 F1990 C1 Hosted At Imgbb Imgbb See below f (x) =x^2 let f' (3) = the instantaneous rate of change in f (x) at x=3 to estimate f' (3) we can use the difference quotient: (f (x deltax) f (x)) (deltax) for x=3 and some small deltax let's choose deltax = 0.01 then, f' (3) approx ( (3 0.01)^2 3^2) 0.01 approx (9.0601 9) 0.01 approx 6.01 now let's find f' (x) as deltax >0 f' (x) = lim (deltax >0) (f (x deltax) f (x)) (deltax. "ph"=2 the ph of a substance is given by: "ph"= log ["h" 3"o"^ ], where: ["h" 3"o"^ ] is the concentration of hydronium ions. here, that concentration is 0.01"m.
D8 D90881 1416 4 C00 B459 2 B9 Fc78180 Fa Hosted At Imgbb Imgbb 7.01"g" notice the coefficients of n 2 and h 2. since the equation has an n 2 and 3h 2, 3 times as many moles of h 2 will be used as n 2 assuming a complete reaction. since we're given the mass of h 2 being used, we can divide that by the molar mass of h 2 to determine how many moles of h 2 will be consumed. 675n here,the kinetic energy of the hammer head got totally converted to the work done in moving the nail through a distance of 10 mm or 0.01 m so, kinetic energy of the hammer during the strike was 1 2 m v^2=1 2×1.5×3^2=6.75j now,if an average force of f had acted on the nail to move it by 0.01 m,then work done by the force will be (f×0.01)j(using w=f*s) so,we can equate both 6.75=f×0.01. E p=206,01 " joule" "it will gain the potential energy ,if an object raises from earth." e p=m*g*h e p=7*9,81*3 e p=206,01 " joule". The point of this problem for f (t)=1 (1 4t) and l=0 is to find the corresponding value of b when epsilon=0.01. this does not prove that lim {t > infty}f (t)=0, but is equivalent to the kind of algebra you would need to do to help you do a proof.
Cef0516 E 38 B1 4 B87 880 B 3 B4 F5 B568241 Hosted At Imgbb Imgbb E p=206,01 " joule" "it will gain the potential energy ,if an object raises from earth." e p=m*g*h e p=7*9,81*3 e p=206,01 " joule". The point of this problem for f (t)=1 (1 4t) and l=0 is to find the corresponding value of b when epsilon=0.01. this does not prove that lim {t > infty}f (t)=0, but is equivalent to the kind of algebra you would need to do to help you do a proof. Well, chi "hcl"~=0.20 chi "hcl"="moles of hcl" "total moles in solution" =n "hcl" (n "hcl" n "water") = ( (44.2*g) (36.46*g*mol^ 1)) ( (44.2*g) (36.46*g*mol^ 1. A gas mixture contains 1.19 g n 2 and 0.79 g o2 in a 1.60 l container at 25 deg c. how do you calculate the mole fraction of n 2?. Combustion of 27.44 g of a compound containing only carbon, hydrogen, and oxygen produces 53.60 gco2 and 27.43 gh2o. what is the empirical formula of the compound?. What is the volume occupied by a 91.8 ⋅ g mass of carbon dioxide that is heated to 517.2 ⋅ k, and subjected to a pressure of 287 ⋅ torr?.
1 A098 B7 E 7 B78 4 C85 8710 C200556 B2 Ee2 Postimages Well, chi "hcl"~=0.20 chi "hcl"="moles of hcl" "total moles in solution" =n "hcl" (n "hcl" n "water") = ( (44.2*g) (36.46*g*mol^ 1)) ( (44.2*g) (36.46*g*mol^ 1. A gas mixture contains 1.19 g n 2 and 0.79 g o2 in a 1.60 l container at 25 deg c. how do you calculate the mole fraction of n 2?. Combustion of 27.44 g of a compound containing only carbon, hydrogen, and oxygen produces 53.60 gco2 and 27.43 gh2o. what is the empirical formula of the compound?. What is the volume occupied by a 91.8 ⋅ g mass of carbon dioxide that is heated to 517.2 ⋅ k, and subjected to a pressure of 287 ⋅ torr?.
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